Ruby在文本文件中找到一个字符串，然后输出在其上找到的行

Question

I need to add the functionality to output the entire line a string is found on. So here's the code I have working so far.

if type == "asa"
    if File.readlines(file).grep(/http server enabled/).any?
        $httpserver_failures.push(file)
        out.puts "FAILED: does have http enabled"
    else
        $httpserver_passes.push(file)
        out.puts "PASSED: does not have http enabled"
    end
elsif type == "ios"
    if File.readlines(file).grep(/no ip http server/).any?
        $httpserver_failures.push(file)
        out.puts "FAILED: does have http enabled"
    else
        $httpserver_passes.push(file)
        out.puts "PASSED: does not have http enabled"
    end
end

So I just need to add a line to also output the line as it's found. I just don't know the syntax.

Thanks

Answer 1

grep method takes a block also. Thus I think you could write as below :

if type == "asa"
  File.readlines(file).grep(/http server enabled/) do |line|
    unless line.empty?
      $httpserver_failures.push(file)
      out.puts "FAILED: does have http enabled"
      puts line # output the line
    else
      $httpserver_passes.push(file)
      out.puts "PASSED: does not have http enabled"
    end
  end
elsif type == "ios"
  File.readlines(file).grep(/no ip http server/) do |line|
    unless line.empty?
      $httpserver_failures.push(file)
      out.puts "FAILED: does have http enabled"
      puts line # output the line
    else
      $httpserver_passes.push(file)
      out.puts "PASSED: does not have http enabled"
    end
  end
end