我们如何使用Python在字符串的开头删除标点符号？

Question

I want to strip all kinds of punctuation at the start of the string using Python. My list contains strings and some of them starting with some kind of punctuation. And how can I strip all type of punctuation from the strings?

For example: If my word is like ,,gets , I want to strip ,, from the word, and I want gets as the result. Also, I want to strip away spaces as well as numbers from the list . I have tried with the following code but it is not producing the correct result.

If 'a' is a list containing some words:

for i in range (0,len(a)):
      a[i]=a[i].lstrip().rstrip()
      print a[i]

Answer 1

You can use strip() :

Return a copy of the string with the leading and trailing characters removed. The chars argument is a string specifying the set of characters to be removed.

Passing string.punctuation will remove all leading and trailing punctuation chars:

>>> import string
>>> string.punctuation
'!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~'

>>> l = [',,gets', 'gets,,', ',,gets,,']
>>> for item in l:
...     print item.strip(string.punctuation)
... 
gets
gets
gets

Or, lstrip() if you need only leading characters removed, rstip() - for trailing characters.

Hope that helps.

Answer 2

在lstrip和rstrip传递要删除的字符

'..foo..'.lstrip('.').rstrip('.') == 'foo'

Answer 3

strip() when used without parameters strips only spaces. If you want to strip any other character, you need to pass it as a parameter to strip function. In your case you should be doing

a[i]=a[i].strip(',')

Answer 4

To remove punctuation, spaces, numbers from the beginning of each string in a list of strings:

import string

chars = string.punctuation + string.whitespace + string.digits    
a[:] = [s.lstrip(chars) for s in a]

Note: it doesn't take into account non-ascii punctuation, whitespace, or digits.

Answer 5

If you want to remove it only from the begining, try this:

    import re
    s='"gets'
    re.sub(r'("|,,)(.*)',r'\2',s)

Answer 6

Assuming you want to remove all punctuation regardless of where it occurs in a list containing strings (which may contain multiple words), this should work:

test1 = ",,gets"
test2 = ",,gets,,"
test3 = ",,this is a sentence and it has commas, and many other punctuations!!"
test4 = [" ", "junk1", ",,gets", "simple", 90234, "234"]
test5 = "word1 word2 word3 word4 902344"

import string

remove_l = string.punctuation + " " + "1234567890"

for t in [test1, test2, test3, test4, test5]:
    if isinstance(t, str):
        print " ".join([x.strip(remove_l) for x in t.split()])
    else:
        print [x.strip(remove_l) for x in t \
               if isinstance(x, str) and len(x.strip(remove_l))]

Answer 7

for each_string in list:
    each_string.lstrip(',./";:') #you can put all kinds of characters that you want to ignore.