[英]Haskell - Return number of chars excluding punctuation and spaces
I've just learned how to count the number of chars in a string using length nameoflist
and I'm wondering if it's possible to count the number of chars without spaces/punctuation? 我刚刚学习了如何使用
length nameoflist
来计算字符串中的字符数,并且我想知道是否可以计算没有空格/标点的字符数?
Any help is appreciated,thanks 任何帮助表示赞赏,谢谢
import Data.Char
length $ filter isAlphaNum nameoflist
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