[英]Find word using reg exp
In a string that includes numeric values like: 在包含数字值的字符串中,例如:
6.1, 6.1.1, 6.1.2.
6.1、6.1.1、6.1.2。
I want to find (and replace) the whole word "6.1"
and ignore other words starting with "6.1"
. 我想查找(并替换)整个单词
"6.1"
而忽略其他以"6.1"
开头的单词。 I tried using \\b
in my reg expression: 我尝试在reg表达式中使用
\\b
:
Dim OrginalString as String = "Sample text with numeric values starting with 6.1 followed by 6.1.1, 6.1.2 "
Dim wordToFind as String = "6.1"
Dim pattern As String = [String].Format("\b({0})\b", wordToFind)
Dim ret As String = Regex.Replace(OrginalString, pattern, "1234",RegexOptions.IgnoreCase)
But it replaces all of the numeric "words" starting with "6.1"
. 但是它将替换所有以
"6.1"
开头的数字“单词"6.1"
。 Here is the result: 结果如下:
ret = "Sample text with numeric values starting with 1234 followed by 1234.1, 1234.2 "
Solutions in VB or C# is OK with me. VB或C#中的解决方案对我来说还可以。
It worked. 有效。 :) Thank you Casimir et Hippolyte!
:)谢谢Casimir et Hippolyte!
You can use a negative lookahead: 您可以使用否定的前瞻:
6\.1(?![.\d])
(?!...)
means "not followed by" and is only a check, not a part of the match result. (?!...)
意思是“不跟随”,仅是检查,而不是比赛结果的一部分。
Note: \\b
is only relative to the \\w
character class, since the .
注意:
\\b
仅相对于\\w
字符类,因为.
isn't in this class, there is a word boundary between 1
and .2
in 6.1.2
不是此类,在
6.1.2
1
和.2
之间存在单词边界
You can add a lookbehind to be sure that your number is preceded with a space or the start of the string, example: 您可以在后面添加一个后缀,以确保您的数字前面带有空格或字符串的开头,例如:
(?<=^|\s)6\.1(?![.\d])
or not preceded with a number or a dot: 或前面没有数字或点:
(?<![.\d])6\.1(?![.\d])
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.