[英]Regex - How to replace the last 3 words of a string with PHP
Trying to wrap the last 3 words in a <span>
tag 尝试将最后3个单词包装在
<span>
标记中
$str = 'Lorem ipsum dolor sit amet';
$h2 = preg_replace('/^(?:\w+\s\w+)(\s\w+)+/', '<span>$1</span>', $str);
Here it is: 这里是:
$h2 = preg_replace('/(\w+\s\w+\s\w+)$/', '<span>$1</span>', $str);
Since its last three words, so make the left side(from begin) as open to have the match. 由于它的最后三个词,所以使左侧(从开始)开放以进行匹配。
Sabuj Hassan's treats numbers and _ as being part of a word as well, so use that if it makes sense. Sabuj Hassan还将数字和_视为单词的一部分,因此请在有意义的情况下使用它。
Assuming "words" are letters delimited by a space: 假设“单词”是由空格分隔的字母 :
$str = 'Lorem ipsum dolor sit amet';
$h2 = preg_replace('/([a-z]+ [a-z]+ [a-z]+)$/i', '<span>$1</span>', $str);
echo $h2;
If you want any non-whitespace considered a word then: 如果您想将任何非空格视为一个单词,则:
$h2 = preg_replace('/(\S+ \S+ \S+)$/', '<span>$1</span>', $str);
There is no reason to use regex here at all if you define words as being bounded by a single space. 如果将单词定义为由单个空格限制,则完全没有理由在此处使用正则表达式。 Instead you can use basic string manipulation to get the desired result.
相反,您可以使用基本的字符串操作来获得所需的结果。
$str = ...; // your input string
$words_with_offsets_in_key = str_word_count($str, 2);
$word_count = count($word_offsets);
if($word_count >= 3) {
// we have at least 3 words
// find offset of word three from end of array of words
// grab third item from end of array
$third_word_from_end = array_slice($words_with_offsets_in_key, $word_count - 3, 1);
// inspect its key for offset value in original string
$offset = key($third_word_from_end);
// insert span into string
$str = substr_replace ( $str , '<span>' , $offset, 0) . '</span>';
}
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