如何在Ruby中获取两个字符之间的字符串？

Question

Okay if I have a string that is a full file path like "Folder/New Folder/test.csv" . How can I get everything between the /'s ? So get "New Folder" .

Thanks!

Answer 1

No need to use a regex at all...

> File.basename(File.dirname("Folder/New Folder/test.csv"))
=> "New Folder"

Answer 2

You don't necessarily have to use a regex to accomplish this task.

String Split

path = "Folder/New Folder/test.csv"
puts path.split('/')[1]

File Operations

path = File.dirname("Folder/New Folder/test.csv")
puts File.basename(path)

Regex

path = "Folder/New Folder/test.csv"
puts path.scan(/\/(.*)\//)[0]

Using any of these ways, you will get the following output:

#=> New Folder

Answer 3

Just do

File.dirname( "Folder/New Folder/test.csv" ).split('/')[-1]
# => "New Folder"

Answer 4

If you wish to use regex:

input = "Folder/New Folder/test.csv"
print input.scan(/\/(.*)\//).flatten

Answer 5

You can do this easily using a regular expression. Note this will yield whatever is between the 1st and 2nd / . So if your String would be "some/longer/path/than/original" , it would yield "longer" .

path = "Folder/New Folder/test.csv"
p path[%r{/([^/]+)/}, 1]
# => "New Folder"