MySQL PHP-根据不同的位置选择位置

Question

Is it possible to sort data based on an order value set on a certaid IDs?

I want to make the following:

    ID - Position
    1  - 3rd
    2  - 4th
    3  - 5th
    4  - 6th
    10 - 7th
    11 - 8th
    12 - 9th
    13 - 10th
    14 - 11th
    83 - 2nd
    84 - 1st

I've been trying to implement this one, but it doesn't generate the correct order:

SELECT * FROM table_name WHERE id IN (1,2,3,4,5,6,7,81,82) ORDER BY id = 3 DESC, id = 4 DESC, id = 5 DESC, id = 6 DESC, id = 7 DESC, id = 8 DESC, id = 9 DESC, id = 1 DESC, id = 2 DESC

If I was unclear, please ask me for more info. Thank you in advance.

Answer 1

SELECT * FROM table_name WHERE id IN (1,2,3,4,5,6,7,81,82) ORDER BY CAST(SUBSTR(position, 1, CHAR_LENGTH(position) - 2) as unsigned)

Answer 2

Yes you can use order by FIELD , below is an example you can modify the way you want.

SELECT * FROM 
table_name 
WHERE id IN (1,2,3,4,5,6,7,81,82)
order by FIELD(id,3,4,5,1,2,6,7,81,82)

http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_field

Answer 3

I think this is sufficient you dont need to add anything in this.

SELECT * FROM table_name WHERE id IN (1,2,3,4,5,6,7,81,82) ORDER BY id DESC

or you can use, if want in particular sequence of ID,

SELECT * FROM  table_name  WHERE id IN (1,2,3,4,5,6,7,81,82) order by FIELD(id,3,4,5,6,7,8,9,1,2)

or you can use ORDER BY CASE