C ++ uint8_t数组长度

Question

I trying to get the size of array, but I gets funny results:

sizeof(new uint8_t[1]) gives me 4 while sizeof(uint8_t) gives me 1.

How do i get the size of an uint8_t array?

Answer 1

new uint8_t[1] is a pointer, not an array.

How do i get the size of an uint8_t array?

For an array of N elements, the size in bytes is

sizeof(uint8_t[N]);

or

N * sizeof(uint8_t);

However, if uint8_t exists, it will be one byte; so in this case the array size is just N .