[英]Submit button not working in php
I have a form and the submit button is not working. 我有一个表单,提交按钮不起作用。 Submit is based on whether someone approves or denies. 提交是基于某人是否批准或拒绝。 Also approve deny dropdown needs to pre-populate if someone goes back to tha page by using a temp id from what they entered. 如果有人通过使用他们输入的临时ID返回到页面,也批准拒绝下拉需要预先填充。
It was working when I use html, but when I add in the php it doesn't work. 当我使用html时,它正在工作,但是当我添加php时它不起作用。 I think it is because I am not calling selectbasic but I don't know where to add the id. 我认为这是因为我没有调用selectbasic但我不知道在哪里添加id。 I have tried different variations and can't get it to work. 我尝试了不同的变化,但无法使其发挥作用。
<form name="iform" id="myform" method="post" onsubmit="submitForm" onreset="" enctype="multipart/form-data" action="submitForm" class="iform">
<label for="Email">Email Address for Officer:</label>
<input class="itext" type="text" value="<?php print $jsonData['Email']; ?>" name="Email" id="Email" />
<br /><br />
<label for="ApproveDeny">Approve or Deny Warrant:</label>
<select class="iselect" name="selectbasic" id="selectbasic">
<?php
$values = array("1" => "Choose an option", "2" => "Approved", "3" => "Denied");
foreach ($values as $value) {
$selectString = '';
if ($value == $jsonData['selectbasic']) {
$selectString = ' selected';
}
print '<option value="' . $value . '"' . $selectString . '>' . $value . '</option>';
}
?>
</select>
<br /><br />
<label> </label><button type="submit2" class="btn btn-success">submit</button>
<input type="hidden" name="tempId" id="tempId" value="<?php print $tempId; ?>" />
</form>
javascript JavaScript的
<script type="text/javascript">
document.getElementById('selectbasic').onchange = function(){
if (this.value=="2") {
newAction='html_form_judge.php';
} else if (this.value=="3") {
newAction='html_form_judgedeny.php';
} else {
newAction='else.php';
}
document.getElementById('myform').action = newAction;
}
</script>
You're setting the value of each option to the name, not numerical key, of each element in your array. 您要将每个选项的值设置为数组中每个元素的名称,而不是数字键。 Do it like this: 像这样做:
foreach ($values as $id => $value) {
...
print '<option value="' . $id . '"' . $selectString . '>' . $value . '</option>';
}
That way, in your javascript, the selected value might actually equal "2" rather than "Approved". 这样,在您的javascript中,所选值实际上可能等于“2”而不是“已批准”。
Try ...action="POST"... for your action attribute. 尝试... action =“POST”...为您的操作属性。 That specifies the type of form submission rather than any function to call prior to sending the form. 这指定了表单提交的类型,而不是在发送表单之前调用的任何函数。
You can remove onrest
from your form element. 您可以从表单元素中删除onrest
。
If you want form reset functionality, you can add an input with the parameter type="reset"
. 如果需要表单重置功能,可以使用参数type="reset"
添加输入。
I also suggest you rename submit2
to submit
. 我还建议你重命名submit2
来submit
。
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