[英]How to extract/expand variadic template parameters
template <typename T1, typename T2>
class Base
{
T1 t1;
T2 t2;
};
template <typename...TN>
class Derived
: public Base< std::tuple<QList<TN...>>,
std::tuple<QVector<TN...>> > //does not work
{
};
Derived<int, double> d;
t1
shall become std::tuple<QList<int>, QList<double>>
t1
将变为std::tuple<QList<int>, QList<double>>
t2
shall become std::tuple<QVector<int>, QVector<double>>
t2
将变为std::tuple<QVector<int>, QVector<double>>
I don't know if this is possible in general. 我不知道这是否可能。 Currently I use preprocessor magic for that.
目前,我为此使用预处理器魔术。 But I hoped that variadic template can do that too.
但是我希望可变参数模板也可以做到这一点。 So, can I do any recursive things or any similar to extract the template?
因此,我可以做任何递归操作或类似的操作来提取模板吗?
As @dyp says, you expanded the pack in the wrong place. 正如@dyp所说,您将扩展包放在错误的位置。 It should be like this:
应该是这样的:
: public Base< std::tuple<QList<TN>...>,
std::tuple<QVector<TN>...> >
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