[英]Ubuntu shell script menu
I am new to shell scripting/ programming. 我是Shell脚本/编程的新手。 I want to create a menu that shows the following: list files, time and date, calendar, password file and exit.
我想创建一个显示以下内容的菜单:列表文件,时间和日期,日历,密码文件和退出。 User should be able to enter their choice and script responds.
用户应该能够输入他们的选择并且脚本响应。 Any help appreciated!!
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while ((choice 1=5))
do
clear
echo "1. List all files"; echo
echo "2. Display date and time"; echo
echo "3. Calendar"; echo
echo "4. Passwd file"; echo
echo "5. Exit"; echo
echo -n "Enter choice"
read choice
case $choice in
1) ls -l;;
2) date;;
3) cal;;
4) cat /etc/passwd;;
5) echo "Thanks and goodbye!";;
*) echo "1..5 only"
esac
sleep 3
done
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