如何将多个表中的多个行插入到另一个表中？

Question

How do I create an insert statement that will insert E_PROVIDER_ID values (PROV_ID, PROV_NAME, IDENTITY_ID) into E_PROVIDER_MAP where IDENTITY_ID_TYPE = 125?

I need the insertion to insert values from the ID table into the mapping table so that:

 E_PROVIDER_ID.PROV_ID = E_PROVIDER_MAP.I_PROV E_PROVIDER_ID.E_PROVIDER_ID = E_PROVIDER_ID.IDENTITY_ID E_PROVIDER_ID.E_PROV_NAME = E_PROVIDER_MAP.I_PROV_NAME E_PROVIDER_ID.E_PROV_NAME = E_PROVIDER_MAP.E_PROV_NAME 

--Create ID Table

create table E_PROVIDER_ID
(
  PROV_ID          VARCHAR2(50),
  PROV_NAME        VARCHAR2(50),
  ID_LINE#         VARCHAR2(50),
  IDENTITY_TYPE_ID VARCHAR2(50),
  ID_TYPE_NAME     VARCHAR2(50),
  IDENTITY_ID      VARCHAR2(50),
)

--INSERT VALUES

insert into E_PROVIDER_ID (PROV_ID, PROV_NAME, ID_LINE#, IDENTITY_TYPE_ID, ID_TYPE_NAME, IDENTITY_ID,)
values ('1005232', 'SMITH, BRIAN EDWARD', '5', '125', 'PROVIDER CODE ID', '020621');
insert into E_PROVIDER_ID (PROV_ID, PROV_NAME, ID_LINE#, IDENTITY_TYPE_ID, ID_TYPE_NAME, IDENTITY_ID,)
values ('1003556', 'SMITH, JOHN STUART', '4', '125', 'PROVIDER CODE ID', '026786');
insert into E_PROVIDER_ID (PROV_ID, PROV_NAME, ID_LINE#, IDENTITY_TYPE_ID, ID_TYPE_NAME, IDENTITY_ID,)
values ('1003595', 'SMITH, RICHARD F.', '5', '125', 'PROVIDER CODE ID', '029091');
insert into E_PROVIDER_ID (PROV_ID, PROV_NAME, ID_LINE#, IDENTITY_TYPE_ID, ID_TYPE_NAME, IDENTITY_ID,)
values ('1003602', 'SMITH, PAUL MATTHEW', '5', '125', 'PROVIDER CODE ID', '029761');
insert into E_PROVIDER_ID (PROV_ID, PROV_NAME, ID_LINE#, IDENTITY_TYPE_ID, ID_TYPE_NAME, IDENTITY_ID,)
values ('1003769', 'SMITH, MARC DROR', '4', '125', 'PROVIDER CODE ID', '029748');
insert into E_PROVIDER_ID (PROV_ID, PROV_NAME, ID_LINE#, IDENTITY_TYPE_ID, ID_TYPE_NAME, IDENTITY_ID,)
values ('1006776', 'SMITH, ULA V.', '6', '125', 'PROVIDER CODE ID', '034415');
insert into E_PROVIDER_ID (PROV_ID, PROV_NAME, ID_LINE#, IDENTITY_TYPE_ID, ID_TYPE_NAME, IDENTITY_ID,)
values ('1006946', 'SMITH, TIMOTHY P.', '7', '125', 'PROVIDER CODE ID', '034687');
insert into E_PROVIDER_ID (PROV_ID, PROV_NAME, ID_LINE#, IDENTITY_TYPE_ID, ID_TYPE_NAME, IDENTITY_ID,)
values ('1007032', 'SMITH, DAVID C.', '7', '125', 'PROVIDER CODE ID', '101754');
commit;

-- Create map table

create table E_PROVIDER_MAP
(
  I_PROV       NUMBER,
  I_PROV_NAME  VARCHAR2(50),
  E_PROV       NUMBER,
  E_PROV_NAME  VARCHAR2(50),
  I_REC_INST   VARCHAR2(8)
)

Answer 1

I think you just want insert . . . select insert . . . select insert . . . select syntax:

insert into E_PROVIDER_MAP(<columns go here>)
    select PROV_ID, PROV_NAME, IDENTITY_ID
    from E_PROVIDER_ID
    where IDENTITY_ID_TYPE = 125;

I cannot readily tell what the list of columns should be for the "map" table.

EDIT:

Based on your comment and the edit to your question:

insert into E_PROVIDER_MAP(I_PROV, IDENTITY_ID, I_PROV_NAME, E_PROV_NAME)
    select PROV_ID, E_PROVIDER_ID, E_PROV_NAME, E_PROV_NAME
    from E_PROVIDER_ID
    where IDENTITY_ID_TYPE = 125;

I do note that these columns seem to have nothing to do with the create table statements in the question.

Answer 2

Because you are selecting from a table with VARCHAR columns you need to do a select insert with a cast.

insert into E_PROVIDER_MAP(I_PROV, IDENTITY_ID, I_PROV_NAME, E_PROV_NAME) select CAST(PROV_ID AS NUMBER), CAST(E_PROV AS NUMBER), I_PROV_NAME, E_PROV_NAME from E_PROVIDER_ID where IDENTITY_ID_TYPE = 125;