Bash脚本删除目录中的文件，但不同文件中列出的文件除外

Question

I have two files , let's say

root@test:~ $ cat File1.txt

name1
name2
name3


root@test:~$ cat File2.txt

name4
name5
name6

and a Directory that has several filenames

root@test:~$ ls

name1
name2
name3
name4
name5
name6
name7
name8
name9

How can I Delete the files which aren't on both .txt files?? so the final result will be

root@test:~$ ls
name1
name2
name3
name4
name5
name6

is it possible to write something in bash to do this???

Answer 1

In the directory you want to delete the files:

for f in *; do
    [ -z $(grep "^${f}$" <(cat /dir/with/File*.txt)) ] && echo rm -f "$f"
done

Will print out a list of files to be deleted. To actually delete them, remove the echo .

Answer 2

I would test with something like this:

while read -r -d $'\0'; do
    if grep -qs "^$REPLY\$" File1 && grep -qs "^$REPLY\$" File2; then
        # Filename found in both File1 and File2: do nothing
        :
    else
        rm -i "$REPLY"
    fi
done < <(find . -maxdepth 1 -type f -print0)

Unless I'm missing something, this should handle filenames with embedded spaces, newlines, and backslashes correctly.

You can remove the interactive flag ( -i ) from rm once you're confident that it's doing what you want.