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迭代python中具有相同索引位置的多个列表

[英]Iterating through multiple lists with same index position in python

I am new to python and I was just trying some list manipulations. 我是python的新手,我只是尝试了一些列表操作。 I have three lists 我有三个清单

A = [10,20,30,40,50,60]
B = [22,44,66,88,12,10]
C = [2,4,6,8,10,20]

I want to iterate over these three lists and for each value of CI want to add half of that value to the corresponding values of A and B. For example for the 1st iteration - half = 2/2= 1 So A = 10 + 1 and B = 22+1 So the final lists should look something like this 我想迭代这三个列表,并且CI的每个值都希望将该值的一半添加到A和B的相应值。例如,对于第一次迭代 - half = 2/2 = 1所以A = 10 + 1并且B = 22 + 1所以最终的列表看起来应该是这样的

A = [11,22,33,44,55,70]
B = [23,46,69,92,17,20]
C = [2,4,6,8,10,20]

As long as the lists all have the same lengths, you can iterate with enumerate() function: 只要列表都具有相同的长度,您就可以使用enumerate()函数进行迭代:

for i, n in enumerate(C):
    A[i] += n/2
    B[i] += n/2

>>> A
[11, 22, 33, 44, 55, 70]
>>> B
[23, 46, 69, 92, 17, 20]
>>> A, B = zip(*((a + c/2, b + c/2) for a, b, c in zip(A, B, C)))

ITs best to use Numpy arrays. 最好使用Numpy阵列。

import numpy as np
A, B, C = map(np.array, [A, B, C])
A, B = A - C/2, B - C/2

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