[英]Adding delimiter every n places in every line
How can I extend this script to add delimiters in every line. 如何扩展此脚本以在每行中添加定界符。
apple123456NewYorkCity
nissan98766BostonMA
...
...
$x = somefile.txt
$y = @( ($x[0..4] -join ''), ($x[5..10] -join ''),
($x[11..17] -join ''),
($x[18..21] -join ''))
$z = $y -join '|'
$z > somenewfile.txt
Is the foreach code like this? foreach代码是这样的吗?
$x| %{@( ($_[0..4] -join ''), ($_[5..10] -join ''),
($_[11..17] -join ''),
($_[18..21] -join ''))}??
And suddenly it is clear what you want. 突然间,您就清楚了想要什么。
Long form: 长表:
$lines = Get-Content "somefile.txt"
ForEach ($x in $lines) {
$y = "$($x[0..4] -join '')|$($x[5..10] -join '')|$($x[11..17] -join '')|$($x[18..21] -join '')"
$z = $y -join '|'
Write-Output $z | Out-File -FilePath "somenewfile.txt" -Append
}
Short form: 简写:
gc somefile.txt | % { "$($_[0..4] -join '')|$($_[5..10] -join '')|$($_[11..17] -join '')|$($_[18..21] -join '')" } >> somenewfile.txt
I got rid of the building an array and joining it, and replaced it with string expansion where the string has the delimiters in it; 我摆脱了建立一个数组并将其连接的问题,并用字符串扩展替换了它,其中字符串中有定界符。 for viewers, the pattern is:
对于观众来说,模式是:
"$()|$()|$()" #expressions in a string, separated by bars
"$($_[0..4] -join '')|.." #each expression is taking characters
#and joining the resulting array into a string
#$_.SubString(n,m) would return a string directly
#but it complains if you go past the end of the
#string, whereas $_[n..m] does not
我将REGEX用于此类工作,以避免零件不同长度的问题:
Get-Content .\somefile.txt | % { $_ -replace '(\D*[^\d]*)(\d*[^\D]*)(.+)','$1 $2 $3' }
another solution with regex: 正则表达式的另一个解决方案:
(cat file) -replace '\d+|\D+','$0 '
apple 123456 NewYorkCity
nissan 98766 BostonMA
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