正则表达式匹配字符或数字

Question

I would like to get parts of a string separated by the type (number or character)

Simplified initial situation:

var content = 'foo123bar456';

Desired result:

result = ['foo', 123, 'bar', 456];

This is what I have so far to match the first "foo"

^(([a-z])|([0-9]))+

I thought this would match either characters [az]+ OR numbers [0-9]+ (which would match 'foo' in this case) but unfortunately it allows both (characters AND numbers) at the same time.

If it would match only characters with the same type I could just add "{1,}" to my regex in order to match all occurrences of the pattern and the world would be a bit better.

Answer 1

Correct regex will be:

([a-zA-Z]+|[0-9]+)

Explanation of the regex is:

NODE                     EXPLANATION
--------------------------------------------------------------------------------
  (                        group and capture to \1:
--------------------------------------------------------------------------------
    [a-zA-Z]+                any character of: 'a' to 'z', 'A' to 'Z'
                             (1 or more times (matching the most
                             amount possible))
--------------------------------------------------------------------------------
   |                        OR
--------------------------------------------------------------------------------
    [0-9]+                   any character of: '0' to '9' (1 or more
                             times (matching the most amount
                             possible))
--------------------------------------------------------------------------------
  )                        end of \1

Answer 2

使用g修饰符以及全局匹配

[a-zA-Z]+|[0-9]+/g