如何根据第一个脚本的结果从另一个shell脚本调用shell脚本？

Question

Shell script 1.sh is like

#/bin/bash

if some java command;
then 
exit 1;
else    
exit 0;
fi

Shell script 2.sh will determine its execution based on the result (1 or 0) from 1.sh

#/bin/bash
readyToDoSomethingIfOne=$(1.sh)

if($readyToDoSomethingIfOne=="1");
then
echo "ready to go";
else    
echo "Not ready yet" ;
fi

It looks like exit command from 1.sh does not pass the value to 2.sh. Is there any good way to do so?

By the way, 1.sh and 2.sh have to be separated for business reasons.

Thanks

Answer 1

#/bin/bash

if 1.sh; then
  echo "ready to go";
else    
  echo "Not ready yet" ;
fi

Answer 2

#/bin/bash
if readyToDoSomethingIfOne=$(1.sh); then # Just use the exit status of the initial script directly.
    …
else
    echo 'nope!'
fi

If you don't actually need the variable at all, just run the script like this:

if ./1.sh; then
  echo "Not ready yet"
  return / exit / continue # Not enough context to know which exit approach is best.
fi

Answer 3

The construct

VAR=$(COMMAND)

assigns the output of COMMAND to the variable VAR. You can get the exit status of the last command from the automatic variable $? . That is

COMMAND
case $? in
  0)
      # do this
      ;;
  1)
      # do that
      ;;
  *)
      # do something else
      ;;
esac

If you only want to distinguish between success ( $? == 0 ) and failure ( $? != 0 ) then you can use the simpler if construct as in your script1.sh .

If using $? , watch out that it changes after every command, so if you need the value for later use, save it in a variable.

COMMAND
status=$?
# now use $status