如何将 argparse 值存储在变量中？

Question

I am trying to add command line options to my script, using the following code:

import argparse

parser = argparse.ArgumentParser('My program')
parser.add_argument('-x', '--one')
parser.add_argument('-y', '--two')
parser.add_argument('-z', '--three')

args = vars(parser.parse_args())

foo = args['one']
bar = args['two']
cheese = args['three']

Is this the correct way to do this?

Also, how do I run it from the IDLE shell? I use the command 'python myprogram.py -x foo -y bar -z cheese' and it gives me a syntax error

Answer 1

That will work, but you can simplify it a bit like this:

args = parser.parse_args()

foo = args.one
bar = args.two
cheese = args.three

Answer 2

use args.__dict__

args.__dict__["one"]
args.__dict__["two"]
args.__dict__["three"]

Answer 3

I'm currently using

import argparse
import sys

parser = argparse.ArgumentParser('My program')
parser.add_argument('--one')
parser.add_argument('--two')
parser.add_argument('--three')

parser.parse_args(namespace=sys.modules[__name__])

print(f"{one}, {two}, {three}")

Is there a reason not to do this?

Answer 4

The canonical way to get the values of the arguments that is suggested in the documentation is to use vars as you did and access the argument values by name:

argv = vars(args)

one = argv['one']
two = args['two']
three = argv['three']