[英]Too few arguments to function `float calcSize(int, int, int, int)'
It keeps telling me too few arguments to function in my float calcSize()
function, even though I'm sending all 4 variables in it.它一直告诉我在我的 float calcSize()
函数中运行的参数太少,即使我在其中发送了所有 4 个变量。 My other question is, does my program make sense?我的另一个问题是,我的程序有意义吗?
#include <stdio.h>
#include <conio.h>
#define PAINT 350.00
//Function Prototype
void displayInstructions();
float calcSize(int , int , int , int );
float calcPaint(float);
float calcCost(float, float);
void displayTotals(float, float, float);
int main()
{
// Variables
int l , w , d, win ;
float s;
float p;
float cP = 32.00;
float c ;
displayInstructions();
//Getting variables
printf("Please enter the number of heights in feet");
scanf("%d",&l);
printf("Please enter the number of width");
scanf("%d",&w);
printf("Please enter the number of doors");
scanf("%d",&d);
printf("Please enter the number of windows");
scanf("%d",&win);
calcSize(l , w , d , win);
calcSize() = s;
calcPaint(s);
calcPaint() = p;
calcCost(p, cP);
calcCost() = c;
displayTotals(s , p , c);
getch();
return 0;
}
//Display function
void displayInstructions()
{
Printf("Welcome to the Green Paint Calculator!");
Printf("\nEnter the height and width of the room (in feet)");
Printf("\nand the number of doors and windows.");
Printf("This program will then calculate how many cans of paint needed");
Printf("\n(based on 2 coats of paint).It will then calculate the cost");
Printf("\nbased on the charge per gallon entered");
}
//Calcsize function
float calcSize(int l, int w, int d, int win)
{
float area, areaDoors, areaWindows;
area = (l + w) * 2 * 8.0;
areaDoors = d * 20;
areaWindows = win * 15;
area -= areaDoors + areaWindows;
return area;
}
//calcPaint function
float calcPaint(float s)
{
float galPaint;
galPaint = s / PAINT * 2;
return galPaint;
}
//calccost function
float calcCost(float p, float cP)
{
return p * cP;
}
//Display total function
void displayTotals(float s, float p, flaot c)
{
printf("\n\nSize of room in square feet: %.2f", s);
printf("\nNumber of gallons needed: %.2f", p);
printf("\nTotal cost to paint room: %.2f", c);
}
You program doesn't make any sense.你的程序没有任何意义。 I don't know what are you trying to do with calcSize() = s;
我不知道你想用calcSize() = s;
做什么calcSize() = s;
. . I think it should be like我认为它应该像
s = calcSize(l , w , d , win);
if you wanna assign the return value of function to s
.如果您想将函数的返回值分配给s
。
its your code that is wrong..... calcSize(l , w , d , win);它的代码是错误的..... calcSize(l , w , d , win); calcSize() = s; calcSize() = s; calcPaint(s); calcPaint(s); calcPaint() = p; calcPaint() = p; calcCost(p, cP); calcCost(p, cP); calcCost() = c; calcCost() = c;
displayTotals(s , p , c); displayTotals(s, p, c);
use as follows...使用如下...
s= calcSize(l , w , d , win);
// calcSize() = s;[this line shows you too-few arguments] and lvalue error
p= calcPaint(s);
//calcPaint() = p;[this line shows you too-few arguments]and lvalue error
c=calcCost(p, cP);
//calcCost() = c; [this line shows you too-few arguments]and lvalue error
displayTotals(s , p , c);
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