[英]PHP counting MYSQL rows that contain the same value in one column
I have a database and there is the column named 'status'. 我有一个数据库,有一个名为'status'的列。 This column could contain five possible values.
此列可能包含五个可能的值。 Now I need to sum number of rows, where the status column contains value 'canceled'.
现在我需要对行数求和,其中status列包含值'cancelled'。 What function in the PHP I should use to count it, please?
我应该使用PHP中的哪些函数来计算它? Thanks for response.
谢谢你的回复。
EDIT: 编辑:
I think here's the complete solution. 我认为这是完整的解决方案。 Correct me if I'm wrong.
如果我错了纠正我。
$canceledsum=mysql_query("SELECT COUNT(*) AS totalcanceled FROM nabidka WHERE status='canceled'");
$d=mysql_fetch_assoc($canceledsum);
echo $d['totalcanceled'];
You are probably looking for this: 你可能正在寻找这个:
SELECT COUNT(*)
FROM yourtable
WHERE status='canceled'
or this query that will count all rows for all different status values: 或者此查询将计算所有不同状态值的所有行:
SELECT status, COUNT(*)
FROM yourtable
GROUP BY status
Edit: if you want to count only records created on the current month: 编辑:如果您只想计算当前月份创建的记录:
SELECT status, COUNT(*)
FROM yourtable
WHERE create_date >= DATE_FORMAT(CURDATE(), '%Y-%m-01')
GROUP BY status
here DATE_FORMAT(CURDATE(), '%Y-%m-01')
will return the first day of the current month, if you don't have records created in the future it will be fine. 这里
DATE_FORMAT(CURDATE(), '%Y-%m-01')
将返回当月的第一天,如果您将来没有创建记录就可以了。
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