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从控制器传递变量到视图

[英]Passing variable to view from controller

Can something like this be done? 可以这样做吗? I want to pass a variable from a public function to my view. 我想将变量从公共函数传递到我的视图。

public function index() {

    $home_data['username']  = "myname";
            $home_data['cool'] = $this->variable;

    $this->load->view('home_view', $home_data);
}

public function a_function() {

      public $variable = "cool";      

}

//EDIT// //编辑//

This is what I m actually trying to accomplish and I m stuck. 这是我实际上想要完成的工作,我陷入了困境。

get_two gets two items from a table. get_two从表中获取两个项目。 I want to add the two items to two variables and pass them to the view. 我想将两个项目添加到两个变量,并将它们传递给视图。

public function get_two() {

           $get_results = $this->home_model->get_two_brands();

            if($get_results != false){

              $html = '';

               foreach($get_results as $result){
                     $html .= '<li><a href="#" class="pick" id="'.$result->id.'">'.$result->brand.'</a></li>';
                }

                 $result = array('status' => 'ok', 'content' => $html);
                    header('Content-type: application/json');
                    echo json_encode($result);
                    exit();

            }

}//public function get_two() {

Should I create two functions like this? 我应该创建两个这样的函数吗? But I don't know how to pass the $get_results array from get_two to the below functions. 但是我不知道如何将$get_results数组从get_two传递给以下函数。 I tried public $get_results = $this->model ... etc but that didn't work. 我尝试了public $get_results = $this->model ... etc但是没有用。

public function result_one() {
    return $resultOne = $get_results[0];
}

public function result_two() {
    return $resultTwo = $get_results[1];
}

I'm not sure I've got the question correctly but what you're trying to achieve is something like this? 我不确定我的问题是否正确,但是您要达到的目标是这样的?

public function index() {

    $home_data['username']  = "myname";
    $home_data['cool'] = $this->a_function();

    $this->load->view('home_view', $home_data);
}

public function a_function() {

  return $variable = "cool";      

} }

/ ** AFTER EDIT ** / / **编辑后** /

Things get complicated (possibly because of my english comprehension). 事情变得复杂(可能是由于我的英语理解能力)。

you said 你说

get_two gets two items from a table. get_two从表中获取两个项目。 I want to add the two items to two variables and pass them to the view. 我想将两个项目添加到两个变量,并将它们传递给视图。

So from the function get_two() you need to get and use the result in this way? 因此,您需要从函数get_two()以这种方式获取和使用结果吗?

public function index() {

    $home_data['username']  = "myname";
    $home_data['cool'] = $this->get_two(); // <- here?

    $this->load->view('home_view', $home_data);
}

So you can try with: 因此,您可以尝试:

public function get_two() {

    $get_results = $this->home_model->get_two_brands();

    if($get_results != false){

       return $get_results;
    }
}

and then 接着

public function index() {

    $home_data['username']  = "myname";

    $home_data['cool'] = $this->get_two();

    $this->load->view('home_view', $home_data);
}

and inside you home_view : 在你里面home_view:

<?php

foreach($home_data['cool'] as $result){
    echo '<li><a href="#" class="pick" id="'.$result->id.'">'.$result->brand.'</a></li>';
}

?>

/ ** AFTER NEW QUESTION ** / / **提出新问题后** /

I need the ids of the two choices as two distinct variables 我需要两个选择的id作为两个不同的变量

So change the index function this way: 因此,以这种方式更改index function

public function index() {

    $home_data['username']  = "myname";
    $home_data['cool'] = $this->get_two(); // <- maybe you don't need this anymore

    list($result1, $result2) = $this->get_two();

    $home_data['resultId1'] = $result1->id;
    $home_data['resultId2'] = $result2->id;

    $this->load->view('home_view', $home_data);
}

Now you're able to use $home_data['resultId1'] and $home_data['resultId1'] inside your view. 现在,您可以在视图内使用$home_data['resultId1']$home_data['resultId1']

I don't know the codeigniter framework so this is why I asked for a part of your view but it looks pretty simple as I check in the doc. 我不知道codeigniter框架,所以这就是为什么我要求您提供部分视图的原因,但是当我签入文档时,它看起来非常简单。 And the doc's are not bad there. 而且文档在那里也不错。

Check for Adding Dynamic Data to the View 检查是否将动态数据添加到视图

public_function() should return something, for ex: public_function()应该返回一些东西,例如:

function public_function() {
 return 'groovy';
}

Then call it in the controller: 然后在控制器中调用它:

public function index() {

    $home_data['username']  = "myname";
    $home_data['cool'] = $this->public_function();

    $this->load->view('home_view', $home_data);
}

Then add to the view somewhere <?php echo $home_data['cool'];?> 然后添加到视图中的某处<?php echo $home_data['cool'];?>

I assume it's wrapped in some class. 我认为它被包裹在某个类中。 So if you cannot return the value you need (for ex. function already returns something else) then do something like this: 因此,如果您无法return所需的值(例如,函数已经返回了其他值),请执行以下操作:

class Someclass {

 public $some_class_variable;

 function public_function() {
  $this->some_class_variable = 'groovy';
 }

 function index() {
  $home_data['cool'] = $this->some_class_variable;
 }

}

You can also define the variable in the constructor, this is one way . 您也可以在构造函数中定义变量,这是一种方法。

CODE: 码:

public function __construct(){
$this->variable = "cool"; 
}
public function index() {

    $home_data['username']  = "myname";
            $home_data['cool'] = $this->variable;

    $this->load->view('home_view', $home_data);
}

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