如何取消引用 GDB 中的内存地址？
[英]how can I de-reference a memory address in GDB?
问题描述
I have the following line in gdb
我在 gdb 中有以下行
8048dc2 movl $0x8049a35, 0x4(%esp)
I want to know how to de-reference the address $0x8049a35 so I can figure out what it is, how do I do that in GDB?我想知道如何取消引用地址 $0x8049a35 以便我可以弄清楚它是什么，我该如何在 GDB 中做到这一点？
1 个解决方案
解决方案1
3 已采纳 2014-03-23 18:43:50
You can for example use x 0x8049a35 .例如，您可以使用x 0x8049a35 。 You can also choose a format, see the gdb built-in help.您还可以选择一种格式，请参阅 gdb 内置帮助。 I am puzzled why you didn't read that before asking on SO.我很困惑为什么你在问 SO 之前没有读过。
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