[英]JOptionPane Input Dialog how to decide if the value is 2 or JOptionPane.CANCEL_OPTION
i use the following Code to get an InputDialog: 我使用以下代码来获取InputDialog:
String c = JOptionPane.showInputDialog("Select number",JOptionPane.OK_OPTION);
I also want that the User only uses IntegerValues between 0 and 100. I handle this by the following code: 我还希望User只使用介于0和100之间的IntegerValues。我通过以下代码处理:
while(notAllowed){
try{
int t =Integer.parseInt(c);
if(t==JOptionPane.CANCEL_OPTION)
{
notAllowed=false;
cancel=true;
}
if(t<=100 && t>0 &¬Allowed)
notAllowed=false;
}
catch( Exception err)
{}
if(notAllowed)
c = JOptionPane.showInputDialog("Only Numbers between 1 and 100 are allowed");
}
Now if the uses types the number 2 its like clicking the Cancel Button because the Value of JOptionPane.CANCEL_OPTION is also 2. So how can i find out if Cancel is clicked or the input Value is 2. 现在,如果使用类型数字2,就像单击取消按钮一样,因为JOptionPane.CANCEL_OPTION的值也是2.那么如何找出是否单击取消或输入值是否为2。
JOptionPane returns null if the user clicks on cancel. 如果用户单击取消,JOptionPane将返回null。 Otherwise the value will be returned.
否则返回值。 I figured that out using this small example:
我想出了这个小例子:
public class JOptionPaneTest {
public static void main(String[] args) {
Object obj = JOptionPane.showInputDialog(null, "test", "test-text");
System.out.println(obj);
}
}
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