从main中的方法打印数组

Question

i have an array returned from method, its like {2,2,3,5,0,0,0,0} and i want to print it to output from main like: 2*2*3*5 , how can I do this ? Here's my code:

RozkladLiczby a=new RozkladLiczby(Integer.parseInt(args[0]));
System.out.println(Arrays.toString(a.czynnikiPierwsze(Integer.parseInt(args[i]))));

When i use Arrays.toString() I get output like {2,2,3,5,0,0,0,0} .

How can I get it like I wrote before? RozkladLiczby is creatig a array of ints and czynnikiPierwsze method is returning an array.

Answer 1

You could iterate over your array to print it in the way you want. Have a look into the Arrays.toString() method source code to get an idea on how to do that.

It should look like something:

int[] arr = a.czynnikiPierwsze(Integer.parseInt(args[i])))
   for (int i = 0; i < arr.length; i++) {
      if (i > 0) {
          System.out.println("*");
      }
   System.out.println(arr[i]);
}

Answer 2

You could just do :

import java.util.Arrays;

public class PrintArray{

 public static void main(String []args){
    String g = Arrays.toString(a.czynnikiPierwsze(Integer.parseInt(args[i])));
    g = g.replace(", 0","");
    g = g.replace(", ","*");
    g = g.replace("[","");
    g = g.replace("]","");
    System.out.println(g);
 }

}

INPUT : {2,2,3,5,0,0,0,0}

OUTPUT : 2*2*3*5

Answer 3

Try something like this:

   String s = "";
    for (int n : myArray){
     s += n + "*";
    }

Being myArray the array of int you have. In case myArray is {2,2,3,5,0,0,0,0} this will print out:

2*2*3*5*0*0*0*0*

You have to take into account the checking for the last element of the array if you don't want to print * after the last element.

Answer 4

Here is an example for printing w/o 0 digits.

public class Main {

    static int a[] = {1,2,3,4,5,6,0,0,0,0};

    public static void main(String args[]){

        for(int i=0; i<a.length; i++){
            if(a[i]!=0)
                System.out.print(a[i]+"*");    

        }
    }
}