删除字符串字符前的空白

Question

I am having difficulty removing white space in front of the character. I am trying to parse the sample string object below:

Mary Whitten: {laptop: 100, tv : 5, xbox: 50, }, James Doe: {laptop: 30, tv: 3,  xbox: 5,}, Jesus Navas: {laptop: 25, tv: 3, xbox: 5},Matt Mart:{laptop:10, xbox: 10}

i also used .split('},') while parsing the above string. The keys that I got:

d=['Mary Whitten', ' James Doe', ' Jesus Navas', 'Matt Mart']

there are some white spaces in front of ' James Doe' and ' Jesus Navas' which I am trying to avoid because keys are sensitive to white spaces ie d['James Doe'] is not same as [' James Doe'] because of the white space in the key. How would I avoid it? Also, I wanted to make the list items case insensitive like:

d=(items.lowercase() for items in d)

Answer 1

Look at strip() , lstrip() and rstrip() . Docs here .

For example:

>>> 'Mary Whitten '.rstrip()
'Mary Whitten'
>>> ' James Doe'.lstrip()
'James Doe'
>>> ' Jesus Navas '.strip()
'Jesus Navas'

If you only want certain characters stripped (such as only whitespace), you can feed the .*strip methods a character or iterable of characters, such as .strip(" ") or '.rstrip("\\?\\.\\!\\n") .

For your purpose, it looks like

d = (items.lower().strip() for items in d)

Answer 2

You can simply do that as follows:

string.strip()

Running this script on " Hello " would give "Hello"

For your code, you would do it as follows:

d = [item.strip() for item in d]

>>> d = (item.lower().strip() for item in d)
>>> print d
['mary whitten', 'james doe', 'jesus navas', 'matt mart']