正则表达式以验证用户输入

Question

I want a regular expression, which should start with alphabet or numbers and followed by alphanumeric character and in between, it may or may not contain forward or backward slash ( \\,/ ).

Highly appreciate your help.

Thanks :)

Answer 1

/^[a-z0-9][\w\\\/]+$/i

1. Start of line ( ^ ).
2. [a-z0-9] - a letter or number - 1 occurrence
3. [\\w\\\\\\/]+ - multiple occurrences of alphanumeric characters (including _ ) or \\ or / .
4. Line end ( $ ).

i gnore-case flag will accept both uppercase and lowercase.

[xyz] specifies a character class meaning that either x or y or z can be matched.

DEMO

If you don't consider 123_asd to be alpha-numeric, use:

/^[a-z0-9][a-z0-9\\\/]+$/i

Hope it helps!

Answer 2

^[a-zA-Z0-9]+[a-zA-Z0-9\/\\]*

This will accept / or \\ only in between.

Edit: Oops:p Missed the numbers, updated. Thanks for pointing out.

Answer 3

Try this regex:

(?i)^[a-z\d][a-z\d\\/]*$

?i treats upper-case letters as lower-case letters.