格式化C ++ setw

Question

I am working on formatting and I am not getting the correct formatting.

Here is my code and here is what I am getting for the output

cout << fixed << setprecision(2) << setw(3) << right << source << setw(20)
                 <<right <<vec[source].cityname
                 << setw(15) << left<< sink << setw(15) << left <<vec[sink].cityname
                 << setw(10) << left << vdist[ij] << "miles\n";

I am getting this:

30      Novosibirsk_RU13             Tokyo_JP       10497.68  miles

And I would like to be getting this:

30 Novosibirsk_RU       13  Tokyo_JP             10497.67 miles

How can I get that space between the name and the number?

I've been working on this for a while but I just can't get the right formatting

Answer 1

You have used the std::right IO manipulator wrongly in your cout statement. To achieve the output as shown in your sample you want vec[source].cityname and vec[sink].cityname obviously left aligned:

cout << fixed << setprecision(2) << setw(3) << right << source << 
                 setw(20) << left <<vec[source].cityname <<
                          // ^^^^
                 setw(3) << left<< sink << 
                   // ^
                 setw(15) << left <<vec[sink].cityname << 
                 setw(10) << left << vdist[ij] << "miles\n";

Also note, if you use setw(n) and n is smaller than the length of the next field ( string ) variable, it won't be cutoff, but shifts the whole output to the right for the number of additional characters.