[英]PDO::FETCH_OBJ php
PDO::FETCH_OBJ -> Returns an anonymous object with property names that correspond to the column names returned in your result set. PDO::FETCH_OBJ -> 返回一个匿名对象,其属性名称与结果集中返回的列名称相对应。 For example:
例如:
Array ( [0] => stdClass Object ( [id] => 3 [email] => frank@frank.com [password] => password [salt] => salt [devices] => 1 [accounttype] => 1 [accountcreated] => 2014-03-26 [confirmed] => 1 [confirmcode] => 0 [logindate] => 2014-03-26 ) )
How do I get the email value???????我如何获得电子邮件值??????? Below is what i have so far
以下是我到目前为止所拥有的
$_db = DB::getInstance();
$_db = $_db->query('SELECT * FROM users WHERE email = ? AND password = ? ', array($email, $pass));
$results = $_db->results();
print_r($results);
print_r($results->email); <<<<<<<<<<<--- does not work!
PLEASE HELP been at this for 24hours.... I know its simple because I have done it before... just cant seem to remember of find any referencing code!请帮我解决这个问题 24 小时......我知道它很简单,因为我以前做过......似乎不记得找到任何引用代码!
You can see in what you pasted that $results is an array of objects, so you need to specify which item in the array to get a proper result for email.您可以在粘贴的内容中看到 $results 是一个对象数组,因此您需要指定数组中的哪个项目才能获得正确的电子邮件结果。
Example:例子:
print_r($results[0]->email);
You should use something like the following:您应该使用以下内容:
foreach ($results as $row) {
print_r($row->email);
}
If you expect to have just one row returned, it is always a good idea to check that.如果您希望只返回一行,检查它总是一个好主意。 You can use count() with your $results variable like this:
您可以将 count() 与 $results 变量一起使用,如下所示:
if (count($results)==1) {
print_r($results[0]->email);
}
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