[英]Return a partial view from a controller?
So, we can return a partial view from a controller like this:所以,我们可以像这样从控制器返回一个局部视图:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Mvc;
using MvcApplication1.Models;
namespace MvcApplication1.Controllers
{
public class HomeController : Controller
{
public ActionResult Index()
{
ViewBag.Message = "Modify this template to jump-start your ASP.NET MVC application.";
return View();
}
public ActionResult About()
{
ViewBag.Message = "Your app description page.";
return View();
}
public ActionResult Contact()
{
ViewBag.Message = "Your contact page.";
return View();
}
public PartialViewResult Address()
{
Address a = new Address
{
Line1 = "111 First Ave N.",
Line2 = "APT 222",
City = "Miami",
State = "FL",
Zip = "33133"
};
return PartialView(@"~/Views/Home/_Address.cshtml", a);
}
}
}
But, how am I supposed to use the returned partial view?但是,我应该如何使用返回的局部视图? I created _Address.cshtml under Views/Home, like this:
我在 Views/Home 下创建了 _Address.cshtml,如下所示:
@model MvcApplication1.Models.Address
<p>
This is a partial view of address.
</p>
<p>
@Model.City
</p>
And, at the end of Views/Home/Contact.cshtml, I added this line:并且,在 Views/Home/Contact.cshtml 的末尾,我添加了这一行:
@Html.Partial(@"~/Views/Home/_Address.cshtml")
And I expect to see the City of my address, but it doesn't show up.我希望看到我的地址所在的城市,但它没有出现。 I am confused.
我很迷惑。
When the partial takes a different model than the method you're including it in you need to use the overload that takes a model parameter and supply the model for the view.当部分采用与包含它的方法不同的模型时,您需要使用采用模型参数并为视图提供模型的重载。 By default it uses the same model as the including view.
默认情况下,它使用与包含视图相同的模型。 Typically you only need the path if it's in a different, non-shared folder.
通常,如果路径位于不同的非共享文件夹中,则您只需要该路径。 If it's in the same controller's folder, using just the name should do the trick.
如果它在同一个控制器的文件夹中,只使用名称应该可以解决问题。
@Html.Partial("_Address", Model.Address)
On the other hand, if you're asking how do I get the partial view from an action included in my page, then you want to use the Action
method instead of the Partial
method.另一方面,如果您问我如何从包含在我的页面中的操作获取局部视图,那么您希望使用
Action
方法而不是Partial
方法。
@Html.Action("Address")
EDIT编辑
To make the partial work you need to pass a Contact
model to the contact view.要使部分工作,您需要将
Contact
模型传递给联系人视图。
public ActionResult Contact()
{
var contact = new Contact
{
Address = new Address
{
Line1 = "111 First Ave N.",
Line2 = "APT 222",
City = "Miami",
State = "FL",
Zip = "33133"
}
}
return View(contact);
}
demo for you:为您演示:
public ActionResult Update(Demo model)
{
var item = db.Items.Where(item => item.Number == model.Number).First();
if (item.Type=="EXPENSIVE")
{
return PartialView("name Partial", someViewModel);
}
}
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