正则表达式从URL中排除文件名

Question

I require a regex that will exclude file name from URL.

Input: 'something.something.com/som/som/som/abcd.html'

Should return: 'something.something.com/som/som/som/'

I created this regex:

((?:[a-z0-9\\.\\_]+)(?:\\/)(?:.*?)(?:\\/))(?:[a-z0-9]+)(?:\\.)(?:[a-z0-9]+)

I tried whatever I can and it is giving correct output (tested at regex101.com [PCRE]).

Do I need to add/delete anything else? Any more suggestions? And don't suggest to use parse_url() , it is useless if URL don't have 'http://'.

Answer 1

Using PHP:

$dir = dirname("something.something.com/som/som/som/abcd.html");

Using regex:

$dir = preg_replace("|[^/]+\.[^/]+$|", "$1", $dir);