查找具有两列唯一组合的所有行

Question

I have this table messages ;

sender_id    recipient_id
1            2
1            3
1            3
2            1
3            1
2            3

I wish to select rows such that:

1. Either sender_id or receiver_id = current_user.id .
2. The other field should be unique.

Ie I want to select unique from table where sender_id = 2 or recipient_id = 2 and I need this result:

sender_id    recipient_id
2            1
2            3

How to do it?
Why? Because I wish to build a facebook-like inbox in which sent and received messages are aggregated, and this query is the bottleneck so far.

I am using rails 3.2 and Postgres 9.3.

Answer 1

SELECT sender_id AS user_id, recipient_id AS other_user_id
FROM   messages
WHERE  sender_id = $current_user_id

UNION
SELECT recipient_id, sender_id
FROM   messages
WHERE  recipient_id = $current_user_id
-- ORDER BY 1, 2  -- optional

UNION (not UNION ALL ) removes duplicates from the result making DISTINCT unnecessary. You might want to add ORDER BY at the end for sorted output.

Assuming a big table with relatively few qualifying rows, two btree indexes typically deliver best performance. One with leading or only sender_id , another one with leading or only recipient_id .

A single multicolumn index on (sender_id, receiver_id) or vice versa also works, but typically slower. See:

• Is a composite index also good for queries on the first field?

Answer 2

With ANSI SQL:

SELECT DISTINCT sender_id, reciepient_id
FROM messages
WHERE (sender_id = current_user.id or reciepient_id = current_user.id)