[英]How to select from mysql data with min and max timestamp for each group of rows
I have a mysql table with data from car gps tracker (lat,lng,speed,time). 我有一个mysql表,其中包含来自汽车gps跟踪器(纬度,经度,速度,时间)的数据。 I want to select positions (latitude,longitude and time) where car has been stopped (speed = 0) longer than 10 min, 30 min, 1 hour etc.
我想选择停车(速度= 0)超过10分钟,30分钟,1小时等的位置(纬度,经度和时间)。
My table looks like this: 我的桌子看起来像这样:
id latitude longitude speed time ----------------------------------------------------------------------- 304 52.388983333333336 17.025338333333334 33.67 2014-03-26 08:00:04 305 52.39029 17.023776666666667 34.65 2014-03-26 08:00:14 306 52.391035 17.021631666666668 32.91 2014-03-26 08:00:24 307 52.39103166666666 17.01917 30.03 2014-03-26 08:00:34 308 52.39089833333333 17.01698 29.33 2014-03-26 08:00:44 309 52.390593333333335 17.01532 9.54 2014-03-26 08:00:54 310 52.39071333333333 17.015056666666666 0 2014-03-26 08:01:04 311 52.39105333333333 17.01499 10.3 2014-03-26 08:01:14 312 52.391485 17.01488 7.82 2014-03-26 08:01:24 313 52.391705 17.014815 0 2014-03-26 08:01:34 314 52.391705 17.014815 0 2014-03-26 08:01:44 315 52.391705 17.014815 0 2014-03-26 08:01:54 316 52.391705 17.014815 0 2014-03-26 08:02:04 317 52.391705 17.014815 0 2014-03-26 08:02:14 318 52.391705 17.014815 0 2014-03-26 08:02:24 319 52.39232333333333 17.014648333333334 7.12 2014-03-26 08:02:34 320 52.392345 17.014635 0 2014-03-26 08:02:44 321 52.392345 17.014635 0 2014-03-26 08:02:54 322 52.392345 17.014635 0 2014-03-26 08:03:04 323 52.392345 17.014635 0 2014-03-26 08:03:15 324 52.392345 17.014635 0 2014-03-26 08:03:25 325 52.392345 17.014635 0 2014-03-26 08:03:35 326 52.392558333333334 17.014471666666665 14.11 2014-03-26 08:03:45 327 52.392316666666666 17.012883333333335 27.47 2014-03-26 08:03:55 328 52.39194333333333 17.010871666666667 28.93 2014-03-26 08:04:05 329 52.39152333333333 17.00893 22.28 2014-03-26 08:04:15 330 52.391575 17.007181666666668 27.01 2014-03-26 08:04:25 331 52.39164 17.00501 26.48 2014-03-26 08:04:35 332 52.39159333333333 17.002895 28.34 2014-03-26 08:04:45 333 52.391641666666665 17.000795 26.39 2014-03-26 08:04:55 334 52.392156666666665 16.999178333333333 16.56 2014-03-26 08:05:05 335 52.39223666666667 16.998796666666667 0 2014-03-26 08:05:15 336 52.39234 16.99819 15.38 2014-03-26 08:05:25 337 52.39261166666667 16.996865 17.1 2014-03-26 08:05:35 338 52.392896666666665 16.995643333333334 20.91 2014-03-26 08:05:45 339 52.39313666666666 16.99468 7.5 2014-03-26 08:05:55 340 52.39331833333333 16.993918333333333 9.1 2014-03-26 08:06:05 341 52.3936 16.992806666666667 16.86 2014-03-26 08:06:15 342 52.393746666666665 16.992065 4.72 2014-03-26 08:06:25
Looking for help, any ideas? 寻找帮助,有什么想法吗?
You need to add an identifier to each "0" record so they can be grouped together. 您需要为每个“ 0”记录添加一个标识符,以便可以将它们分组在一起。 One simple measure is the number of non-zero records before it in the data.
一种简单的度量是数据中位于它之前的非零记录数。
select latitude, longitude, min(time) as StartTime, max(time) as EndTime
from (select t.*,
(select count(*)
from tracker t2
where t2.time <= t.time and
t2.speed > 0
) as grp
from tracker t
) t
group by grp, latitude, longitude;
You can then use a having
clause to get the rows you are interested in: 然后,您可以使用
having
子句获取您感兴趣的行:
having max(time) >= min(time) + interval 1 hour
For instance. 例如。
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