[英]select last row in mysql with no-auto incremental
I'm trying to make a temp logging database. 我正在尝试建立一个临时日志记录数据库。 Still on the learnig level. 仍处于学习水平。
How do I get the last row from the database? 如何从数据库中获取最后一行?
select * from tempdat order by tdate desc limit 1
gives the first entry of the day but I want the last. 给出当天的第一条记录,但我想要最后一条。 See below, it could return the entry whit time 21:25:03
如下所示,它可能会返回输入21:25:03
时间21:25:03
+------------+----------+------+-------------+
| 2014-03-29 | 21:20:02 | inne | 22.875 |
| 2014-03-29 | 21:25:03 | inne | 22.875 |
+------------+----------+------+-------------+
1933 rows in set (0.16 sec)
mysql> select * from tempdat order by tdate desc limit 1;
+------------+----------+------+-------------+
| tdate | ttime | zone | temperature |
+------------+----------+------+-------------+
| 2014-03-29 | 00:00:03 | inne | 21.250 |
+------------+----------+------+-------------+
1 row in set (0.03 sec)
Just use two criteria for ordering: first tdate
, then ttime
. 只需使用两个条件进行排序:首先是tdate
,然后是ttime
。 For example: 例如:
SELECT *
FROM tempdat
ORDER BY tdate DESC, ttime DESC
LIMIT 1;
Note that order direction should be specified after each column used. 请注意,应在使用的每一列之后指定顺序方向。 ORDER BY tdate, ttime DESC
will first order all the records by tdate ASC
. ORDER BY tdate, ttime DESC
将首先按tdate ASC
所有记录进行排序。
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