使用关联和可交换运算符折叠/减少期货清单

Question

Consider the following:

import scala.concurrent._
import scala.concurrent.duration.Duration.Inf
import scala.concurrent.ExecutionContext.Implicits.global

def slowInt(i: Int) = { Thread.sleep(200); i }
def slowAdd(x: Int, y: Int) = { Thread.sleep(100); x + y }
def futures = (1 to 20).map(i => future(slowInt(i)))

def timeFuture(fn: => Future[_]) = {
  val t0 = System.currentTimeMillis
  Await.result(fn, Inf)
  println((System.currentTimeMillis - t0) / 1000.0 + "s")
}

both of the following print ~2.5s:

// Use Future.reduce directly (Future.traverse is no different)
timeFuture { Future.reduce(futures)(slowAdd) }

// First wait for all results to come in, convert to Future[List], and then map the List[Int]
timeFuture { Future.sequence(futures).map(_.reduce(slowAdd)) }

As far as I can understand, the reason for this is that Future.reduce/traverse is generic and therefore does not run faster with an associative operator, however, is there an easy way to define a computation where the folding/reducing would start as soon as at least 2 values are available (or 1 in the case of fold ), so that while some items in the list are still being generated, the already generated ones are already being computed on?

Answer 1

Scalaz has an implementation of futures that includes a chooseAny combinator that takes a collection of futures and returns a future of a tuple of the first completed element and the rest of the futures:

def chooseAny[A](h: Future[A], t: Seq[Future[A]]): Future[(A, Seq[Future[A]])]

Twitter's implementation of futures calls this select . The standard library doesn't include it (but see Viktor Klang's implementation pointed out by Som Snytt above). I'll use Scalaz's version here, but translation should be straightforward.

One approach to getting the operations to run as you wish is to pull two completed items off the list, push a future of their sum back on the list, and recurse (see this gist for a complete working example):

def collapse[A](fs: Seq[Future[A]])(implicit M: Monoid[A]): Future[A] =
  Nondeterminism[Future].chooseAny(fs).fold(Future.now(M.zero))(
    _.flatMap {
      case (hv, tf) =>
        Nondeterminism[Future].chooseAny(tf).fold(Future.now(hv))(
          _.flatMap {
            case (hv2, tf2) => collapse(Future(hv |+| hv2) +: tf2)
          }
        )
    }
  )

In your case you'd call something like this:

timeFuture(
  collapse(futures)(
    Monoid.instance[Int]((a, b) => slowAdd(a, b), 0)
  )
)

This runs in just a touch over 1.6 seconds on my dual core laptop, so it's working as expected (and will continue to do what you want even if the time taken by slowInt varies).

Answer 2

To get similar timings to you, I had to use a local ExecutionContext like( from here ):

implicit val ec = ExecutionContext.fromExecutor(Executors.newCachedThreadPool())

After that, I got better performance by splitting up the list and starting the work on each list by assigning them to vals(based on remembering that futures in a for-comprehenion are handled in order unless they are assigned to vals before the for-comprehenion). Because of the associative nature of the lists, I could then re-combine them with one more call to the same function. I modified the timeFuture function to take a description and print the result of the addition:

def timeFuture(desc: String, fn: => Future[_]) = {
  val t0 = System.currentTimeMillis
  val res = Await.result(fn, Inf)
  println(desc + " = " + res + " in " + (System.currentTimeMillis - t0) / 1000.0 + "s")
}

I'm new to Scala, so I'm still working out re-using the same function at the last step(I think it should be possible) so I cheated and created a helper function:

def futureSlowAdd(x: Int, y: Int) = future(slowAdd(x, y))

Then I could do the following:

timeFuture( "reduce", { Future.reduce(futures)(slowAdd) } )

val right = Future.reduce(futures.take(10))(slowAdd)
val left = Future.reduce(futures.takeRight(10))(slowAdd)
timeFuture( "split futures", (right zip left) flatMap (futureSlowAdd _).tupled)

With that last zip etc from here .

I think this is parallel-izing the work and recombining the results. When I run the those, I get:

reduce = 210 in 2.111s
split futures = 210 in 1.201s

I've used a hard-coded pair of takes, but my idea is the whole list splitting could be put into a function and actually re-use the associative function handed to both right and left branches( with slightly unbalanced trees allowed due to remainders ) at the end.

---

When I randomize the slowInt() and slowAdd() functions like:

def rand(): Int = Random.nextInt(3)+1
def slowInt(i: Int) = { Thread.sleep(rand()*100); i }
def slowAdd(x: Int, y: Int) = { Thread.sleep(rand()*100); x + y }

I still see "split futures" completing sooner than "reduce". There appears to be some overhead to starting up, that affects the first timeFuture call. Here's a few examples of running them with the startup penalty over "split futures":

split futures = 210 in 2.299s
reduce = 210 in 4.7s

split futures = 210 in 2.594s
reduce = 210 in 3.5s

split futures = 210 in 2.399s
reduce = 210 in 4.401s

On a faster computer than my laptop and using the same ExecutionContext in the question I don't see such large differences(without the randomization in the slow* functions):

split futures = 210 in 2.196s
reduce = 210 in 2.5s

Here it looks like the "split futures" only leads by a little bit.

---

One last go. Here's a function (aka abomination) that extends the idea I had above:

def splitList[A <: Any]( f: List[Future[A]], assocFn: (A, A) => A): Future[A] = {
    def applyAssocFn( x: Future[A], y: Future[A]): Future[A] = {
      (x zip y) flatMap( { case (a,b) => future(assocFn(a, b)) } )
    }
    def divideAndConquer( right: List[Future[A]], left: List[Future[A]]): Future[A] = {
      (right, left) match {
        case(r::Nil, Nil) => r
        case(Nil, l::Nil) => l
        case(r::Nil, l::Nil) => applyAssocFn( r, l )
        case(r::Nil, l::ls) => {
          val (l_right, l_left) = ls.splitAt(ls.size/2)
          val lret = applyAssocFn( l, divideAndConquer( l_right, l_left ) )
          applyAssocFn( r, lret )
        }
        case(r::rs, l::Nil) => {
          val (r_right, r_left) = rs.splitAt(rs.size/2)
          val rret = applyAssocFn( r, divideAndConquer( r_right, r_left ) )
          applyAssocFn( rret, l )
        }
        case (r::rs, l::ls) => {
          val (r_right, r_left) = rs.splitAt(rs.size/2)
          val (l_right, l_left) = ls.splitAt(ls.size/2)
          val tails = applyAssocFn(divideAndConquer( r_right, r_left ), divideAndConquer( l_right, l_left ))
          val heads = applyAssocFn(r, l)
          applyAssocFn( heads, tails )
        }
      }
    }
    val( right, left ) = f.splitAt(f.size/2)
    divideAndConquer( right, left )
  }

It takes all the pretty out of Scala to split the list up non-tail recursively and assign the futures to values as soon as possible(to start them).

When I test it like:

timeFuture( "splitList", splitList( futures.toList, slowAdd) )

I get the following timings on my laptop using the newCachedThreadPool() :

splitList = 210 in 0.805s
split futures = 210 in 1.202s
reduce = 210 in 2.105s

I noticed that the "split futures" timings could be invalid because the futures are started outside of the timeFutures block. However, the splitList function should be called correctly inside the timeFutures function. One take-away for me is the importance of picking an ExecutionContext that's best for the hardware.

Answer 3

The answer below will run in 700ms on a 20 core machine, which given what needs to run in sequence is as well as one can do on any machine with any implementation (20 parallel 200ms slowInt calls followed by 5 nested 100ms slowAdd calls). It runs in 1600ms on my 4 core machine, which is as well as one can do on that machine.

When the slowAdd calls are expanded, with f representing slowAdd :

f(f(f(f(f(x1, x2), f(x3, x4)), f(f(x5, x6), f(x7, x8))), f(f(f(x9, x10), f(x11, x12)), f(f(x13, x14), f(x15, x16)))), f(f(x17, x18), f(x19, x20)))

The example you provided that uses Future.sequence will run in 2100ms on a 20 core machine (20 parallel 200ms slowInt calls followed by 19 nested 100ms slowAdd calls). It runs in 2900ms on my 4 core machine.

When the slowAdd calls are expanded, with f representing slowAdd :

f(f(f(f(f(f(f(f(f(f(f(f(f(f(f(f(f(f(f(x1, x2), x3), x4), x5), x6), x7), x8), x9), x10), x11), x12), x13), x14), x15) x16) x17) x18) x19) x20)

The Future.reduce method calls Future.sequence(futures).map(_ reduceLeft op) so the two examples you provided are equivalent.

My answer uses a combine function that takes a list of futures and an op , a function that combines two futures into one as parameters. The function returns the op applied to all pairs of futures and pairs of pairs and so on until one future remains, which is returned:

def combine[T](list: List[Future[T]], op: (Future[T], Future[T]) => Future[T]): Future[T] =
  if (list.size == 1) list.head
  else if(list.size == 2) list.reduce(op)
  else list.grouped(2).map(combine(_, op)).reduce(op)

Note: I modified your code a bit to match my style preferences.

def slowInt(i: Int): Future[Int] = Future { Thread.sleep(200); i }
def slowAdd(fx: Future[Int], fy: Future[Int]): Future[Int] = fx.flatMap(x => fy.map { y => Thread.sleep(100); x + y })
var futures: List[Future[Int]] = List.range(1, 21).map(slowInt)

The code below uses the combine function for your case:

timeFuture(combine(futures, slowAdd))

The code below updates your Future.sequence example for my modifications:

timeFuture(Future.sequence(futures).map(_.reduce{(x, y) => Thread.sleep(100); x + y }))