获取具体类型并创建接口类型参数的实例？

Question

Let say I the construcor,

    public MyClass(Manager<Iinterface> manager)
    {
         // How can i get the type of Iinterface and then create an instance
    }

Is it possible that I can make this constructor generic? like,

    public MyClass<T>(Manager<T> manager) where T is Iinterface
    {
         // How can i get the type of Iinterface and then create an instance
    }

Answer 1

You need to define this with the class itself, not the constructor. If you can't make the class itself generic, then static "Create" method could do this. But the, there is probably problem of passing the instance of Manager<T> to Manager<Iinterface> , because classes cannot be covariant.

public class MyClass
{
    public MyClass(Manager<Iinterface> manager) 
    {
        // How can i get the type of Iinterface and then create an instance
    }
    public static MyClass Create<T>(Manager<T> manager) where T : Iinterface, new()
    {
        Type tType = typeof(T);
        T tInstance = new T();

        return new MyClass([some parameters]);
    }
}