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获得所有评论,包括其对某票的投票

[英]get all comments including its votes for a post

I have following three tables in mysql . 我在mysql有以下三个表。

postid | postid | post_content => posts post_content => 帖子

commentid | commentid | post | 发布| comment_content => comments comment_content => 评论

commentvoteid | 评论| comment | 评论| voter => comment_votes 选民=> comment_votes

I want to fetch all the comments , counting its votes for a post . 我想获取所有的commentscounting its votespost

commentid | commentid | comment_content | comment_content | comment_votes => my_result comment_votes => my_result

I have tried the following query but not getting the desired result. 我尝试了以下查询,但未获得所需的结果。

SELECT commentid,comment_content,count_comments.total AS comment_votes
FROM comments
INNER JOIN(SELECT COUNT(*) AS total FROM comment_votes WHERE comment=comments.commentid) AS count_comments
WHERE post={$postId}

Is it possible to fetch the result as I wanted? 是否可以根据需要获取结果? How can I do that? 我怎样才能做到这一点?

You can use GROUP BY to achieve what you want: 您可以使用GROUP BY实现所需的功能:

SELECT commentid,comment_content,COUNT(*) AS total
FROM comments
INNER JOIN comment_votes ON (comment_votes.comment=comments.commentid)
WHERE post={$postId}
GROUP BY commentid;

The method that you are trying uses a correlated subquery. 您正在尝试的方法使用相关的子查询。 You can do this, but the correlated subquery needs to go into the select clause: 您可以执行此操作,但是相关的子查询需要进入select子句:

SELECT c.commentid, c.comment_content,
       (SELECT COUNT(*) FROM comment_votes cv WHERE cv.comment = c.commentid
       ) AS comment_votes
FROM comments c
WHERE post={$postId};

Normally, I much prefer the group by approach but sometimes in MySQL this can be faster. 通常,我更喜欢采用group by方式,但有时在MySQL中这可以更快。

maybe like this: 也许像这样:

select a.commentid, a.comment_content, count(b.*) as total from (
select commentid, comment_content from comments where post={$postId}) a
join comment_votes b on b.comment = a.commentid
group by a.commentid, a.comment_content;

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