关于指针的问题

Question

I have an API for a function that gets ***int as a parameter.

void APIfunc(int ***in_variable)

I write a new function and I have to use this APIfunc .

I want to use a local int in my function (and not int*** ) but I want to pass it to the APIfunc (that gets int**** ).

How can I do it?

Answer 1

Relying only on syntax,

int foo;
int *bar = &foo;
int **bar2 = &bar;
APIfunc(&bar2);

However, just read function documentation. If is unbelievable that it takes so deep pointer chain just to modify single value; must be something much more sophisticated.

Answer 2

The way you call the function depends on whether it allocated memory or it just accesses the memory.

Case: It Allocates Memory

Since it does not seem to have arguments about the size of objects, the type of objects, number of objects, does it assume them? In that case, you need to call it thus:

int** in_variable;
APIfunc(&in_variable);

Case: It Just Accesses The Memory

You must have the data allocated somewhere. You need to call it thus:

int*** in_variable;
// Allocate memory and fill up the data
// ...

// Call the function
APIfunc(in_variable);

Hope that clarifies a few things for you.