作为守护程序运行时，Shell脚本不起作用

Question

I got a simple script (to measure CPU overhead)

#!/bin/bash

WAIT=2
i=1
while :
do
    # Obtain the cpu usage
    top -n 1 > t.$i

    i=$(($i+1))
    sleep $WAIT

done  

When I run it as

./Script.sh

It works as expected.

But when I run it as

./Script.sh&

it does nothing (files are not created). What am I missing here?

Answer 1

Change the line where you invoke top to be:

top -b -n 1 > t.$i

This enables batch mode - good call Karoly