网址索引处查询中的非法字符

Question

http://search-gf-slvaax6ij6m7ohb7at3ki2kvua.us-east-1.xxxx.yyy.com/2013-01-01/search?q=abc&facet.mod={sort:'count'}&facet.topic={sort:'count'}

this url gives me a error whwn i access through get method in android

error:Illegal character in query at index

Answer 1

尝试使用URL编码查询字符串中的字符，如下所示：

http://search-gf-slvaax6ij6m7ohb7at3ki2kvua.us-east-1.xxxx.yyy.com/2013-01-01/search?q=abc&facet.mod=%7bsort%3a%27count%27%7d&facet.topic=%7bsort%3a%27count%27%7d

Answer 2

You have three solutions:

• the quick one: use the constructor of the URI class;
• the medium one: use Guava's UrlEscapers.urlPathSegmentEscaper() (which does the job for query parameters despite its name);
• the "big" one: use a URI Template (RFC 6570) .

All three will produce reliable results for your needs.