了解函数指针声明

Question

I have to describe the following code:

    char *(**f[][]) ();

I understand the "char *" at the beginning and the "()" at the end: It's a function which doesn't have arguments and returns a pointer to char. But what does " ( * * f [ ][ ] ) " mean?

Can anyone help me please? Thanks =D

Answer 1

There's a very useful website you might want to know about: http://cdecl.org/

declare f as array of array of pointer to pointer to function returning pointer to char

In a bit easier to read english, f is a 2d array of pointers to function pointers, that return strings (or pointers to characters).

Quite why you'd need that I have no idea.