SQL Oracle日期时间字符串格式过滤器

Question

In oracle, I have table called Ship as shown below;

The date and time are present in a single column as string format.

f_ID      f_type    f_date

1001      A 3/30/14 12:00:44 PM

1001      B 3/30/14 10:05:45 AM

1002      A 2/4/14 11:31:11 AM

1002      B 2/3/14 9:43:21 AM

1003      A 2/3/14 9:37:04 AM

1003      B 12/13/14 10:13:43 AM

1004      A 2/3/14 10:49:50 AM

1005      B 2/3/14 11:00:43 AM

1006      A 2/3/13 11:02:28 AM

1006      B 2/3/14 11:07:23 AM

1006      C 2/3/14 9:19:11 AM

1007      A 2/4/14 11:32:30 AM

1007      B 2/4/14 11:32:30 AM

1007      C 2/4/14 11:32:30 AM

1007      D 2/4/14 11:32:30 AM

I wish to query/list IDs ( f_ID ) which only have exact date for each record, but the time stamps can be different.

How can I query this in Oracle? I'm having difficulty in querying as the date and time are merged in a single column.

The result should be

f_ID    f_type  f_date

1001    A   3/30/14

1001    B   3/30/14

1004    A   2/3/14 

1005    B   2/3/14 

1007    A   2/4/14 

1007    B   2/4/14 

1007    C   2/4/14 

1007    D   2/4/14 

Answer 1

To get the list of s_id and dates, use an aggregation with a having clause:

select s.s_id, trunc(date), count(*)
from ship s
group by s.s_id, trunc(date)
having min(date) <> max(date)

EDIT:

If your date is a string, then you should fix the data. The format that you have is awful. If you have to store a date as a string, always use the ISO standard YYYY-MM-DD HH:MI:SS format (or something similar). But you can still do what you want:

select s.s_id, substr(date, 1, instr(date, ' ')), count(*)
from ship s
group by s.s_id, substr(date, 1, instr(date, ' '))
having min(date) <> max(date)

Answer 2

I would do:

select f_ID, f_type, trunc(f_date) f_date
from Ship
order by f_date;

This will allow you to detect the lines with same date, whatever the timestamp.

Answer 3

You can ignore the time using the TRUNC function:

SELECT fdid
FROM ship
WHERE TRUNC(ship.date_field) = SOME_DATE;

If you just want to get all the possible dates:

SELECT DISTINCT(TRUNC(date_field))
FROM ship;

Answer 4

This should do what you need:

Select f_id, f_type, SubStr(f_date, 1, InStr(f_date, ' '))
From Ship s 
Where Exists( Select 1
                From Ship x 
               Where SubStr(s.f_date, 1, InStr(s.f_date, ' ')) = 
                     SubStr(x.f_date, 1, InStr(x.f_date, ' '))
                 And s.f_date <> x.f_date )
Order By f_id, f_type