如何找到一个字符数组中的数字？

Question

How can I find which characters in a char[] are numbers?

char[] example = { '2', 'a', '4', 'f', 'u', 'i', '6' };

if(example[3] == ???) 
{
  Console.WriteLine(example[3].toString());
}

Answer 1

char.IsDigit

So:

if (Char.IsDigit(example[3]))
{
   Console.WriteLine(...);
}

If you want all the chars:

IEnumerable<char> digitList = example.Where(c => Char.IsDigit(c));
//or
char[] digitArray = example.Where(c => Char.IsDigit(c)).ToArray();

Use Char.IsNumber if you want all the extra "numbers" in Unicode, specifically:

Numbers include characters such as fractions, subscripts, superscripts, Roman numerals, currency numerators, encircled numbers, and script-specific digits.

Answer 2

Quite simply there is a method Char.IsNumber()

with which you can test:

char[] example = { '2', 'a', '4', 'f', 'u', 'i', '6' };

if(Char.IsNumber(example[3]))

{

  Console.WriteLine(example[3].toString());

}

Answer 3

If you want to get all the numbers:

var numbers = example.Where(char.IsDigit);

If you want to check whether specific char is number or not:

if(char.IsDigit(example[3]))

Answer 4

static void Main(string[] args)
        {

            char[] example = { '2', 'a', '4', 'f', 'u', 'i', '6' };

            if (char.IsDigit(example[3]))

            {

                Console.WriteLine(example[3]);

            }

        }