如何使用“ xsl：attribute”设置显示图像的src-URL？

Question

The code below does not show the image I want to display:

<img">
    <xsl:attribute name="src">
       <xsl:value-of select="//image"/>
       </xsl:attribute>
</img>

although the path to the image exists! Any idea what is wrong on this code?

Answer 1

You can use this

<img>
 <xsl:attribute name="src">
  <xsl:value-of select='imgsource'/>
 </xsl:attribute>
</img>

BUT

inside you xml there must be the path to the image with the variable imgsource, like this:

   <imgsource>http://www.test.com/Images/image.JPG</imgsource>

hence imgsource is like a variable not the path to the image.

Answer 2

You can try do this with variable

<xsl:variable name="imgSrc" select="//image" />
<img src="$imgSrc" alt=""/>