如何使用正则表达式输入数字？

Question

I have a string which has digit and words I want to use regex in java.

String  s="S.No.DistrictMarketPrice 1 Agra Achhnera NIL 2 Agra Agra 1450 3 Agra Fatehabad NIL 4 Agra Fatehpur Sikri 8765 5 Agra Jagner NIL 6 Agra Jarar NIL 7 Agra Khairagarh NIL 8 Agra Shamshabad NIL 9 Aligarh Atrauli 1298 10 Aligarh Chharra NIL";

I want to break this string. I want every string in new line which should start from only exact serino

How can I get this output

S.No  .District  Market                Price
1      Agra      Achhnera              NIL
2      Agra      Agra                 1450
3      Agra      Fatehabad             NIL
4      Agra      Fatehpur Sikri       8765 

Answer 1

You can replace each number by a new line + the number:

String multiline = s.replaceAll("(\\d+)", "\n$1");

• (\\\\d+) captures the number
• $1 refers to the captured number

Answer 2

Replace any instance of one or more digits with the system line separator followed by the matched digit(s).

As such:

String  s = "S.No.DistrictMarketPrice 1 Agra Achhnera NIL 2 Agra Agra NIL 3 Agra Fatehabad NIL 4 Agra Fatehpur Sikri NIL 5 Agra Jagner NIL 6 Agra Jarar NIL 7 Agra Khairagarh NIL 8 Agra Shamshabad NIL 9 Aligarh Atrauli NIL 10 Aligarh Chharra NIL";

System.out.println(
    s.replaceAll("\\d+", System.getProperty("line.separator") + "$0")
);

Output

S.No.DistrictMarketPrice 
1 Agra Achhnera NIL 
2 Agra Agra NIL 
3 Agra Fatehabad NIL 
4 Agra Fatehpur Sikri NIL 
5 Agra Jagner NIL 
6 Agra Jarar NIL 
7 Agra Khairagarh NIL 
8 Agra Shamshabad NIL 
9 Aligarh Atrauli NIL 
10 Aligarh Chharra NIL

Answer 3

Use this one:

String []splits = s.split("(?<!\\d)(?=\\d+)");

splits contains lines per index:

S.No.DistrictMarketPrice 
1 Agra Achhnera NIL 
2 Agra Agra NIL 
3 Agra Fatehabad NIL 
4 Agra Fatehpur Sikri NIL 
5 Agra Jagner NIL 
6 Agra Jarar NIL 
7 Agra Khairagarh NIL 
8 Agra Shamshabad NIL 
9 Aligarh Atrauli NIL 
10 Aligarh Chharra NIL