如何在C＃中获取Unicode字符的十六进制表示形式？

Question

Here is my code:

var hexString = BitConverter.ToString(Encoding.Unicode.GetBytes("ABCD"));

hexString = Regex.Replace(hexString, "[-]", string.Empty);

I get the result:

4100420043004400

I should get:

0041004200430044

That looks like a trailing, ending with "00" problem but I actually get other errors when trying it with special characters.

For instance the greek letter Ο

Should be 039f but my code gives me 9F03

I even tried the below code that I found in another question:

public static string ByteArrayToString(byte[] ba)
{
    StringBuilder hex = new StringBuilder(ba.Length * 2);
    foreach (byte b in ba)
        hex.AppendFormat("{0:x2}", b);
    return hex.ToString();
}

The result is the same.

Answer 1

You get Unicode encoded in Little Endian .

Try Encoding.BigEndianUnicode - it will give you what you want (ie 0041004200430044 for 'ABCD') - just change Unicode to BigEndianUnicode.