如何在AJAX URL中添加变量

Question

I have a function in php that need an id and i need to add a variable in my ajax url the id

PHP Code:

function get_json_selected($purpose) 
    {
        //echo $this->input->post("ids");
        $ids = explode(",", $this->input->post("ids"));
        $site_url = site_url($this->router->class);
        if ($purpose == "EQUIPEMENT"){
            $this->db->select(
                               'a.id,
                                a.manufacturer,
                                a.description,
                                a.serial_no,
                                a.part_no,
                                a.status, 
                                a.availability,
                                getReturnStatus(a.id) as return_status',
                                FALSE
                            );

            $this->db->where_in('a.id', array_unique($ids));

            $result = $this->db->get("equipments a")->result_array();
            echo json_encode(array("spares" => $result));
        } else {
            $this->db->select(
                               'a.id,
                                a.manufacturer,
                                a.description,
                                a.serial_no,
                                a.part_no,
                                a.status, 
                                a.availability,
                                getReturnStatus(a.id) as return_status',
                                FALSE
                            );

            $this->db->where_in('a.id', array_unique($ids));

            $result = $this->db->get($this->active_table." a")->result_array();
            echo json_encode(array("spares" => $result));
        }


    }   

Ajax Code:

this is just example of the variable of id.

$purpose = "EQUIPMENT"; // how can i add this php variable to ajax url

url: "<?=site_url('equip_request/get_json_selected');?>", // this is the current code how can i add id in this url

or is this code right?

url: "<?=site_url('equip_request/get_json_selected/'.$purpose);?>"

Answer 1

var purpose = '<?php echo json_encode($purpose); ?>';

url: 'example.php?=' + purpose;

+ is the concatenator in javascript. hope this helps. spend plenty of time and add plenty of security to echoing that var into javascript. else you could find yourself viction of xss.