在C中使用argv和argc解析命令行

Question

I'm trying to figure out how to get commands from the command line and when getting that command perform a certain method. I can't get the code to recognize the inputted values. Any ideas?

getopts, fgets, or anything of the sort hasn't worked either.

int main(int argc, char *argv[]){
int i = 1;

while((argc > 1) && (argv[i] != "d")) {
   switch (argv[i]) {
     case: "a":
       callMethodA(atoi(argv[i+1]));
       break;
     case: "b":
       callMethodB(atoi(argv[i+1]));
       break;
     case: "c":
       callMethodC(atoi(argv[i+1]));
       break;
     default:
       printf("command not recognized");
   }
   argc++
   i+=2;
}

what's suppose to happen is say inputted as:

a 3 5 1 b 2 1 c      4

it would call the function callMethodA() with the parameter int of 3 so

callMethodA(3);
callMethodA(5);
callMethodA(1);
callMethodB(2);
callMethodB(1);
callMethodC(4);

EDIT from suggestion by PureW

int i = 1;

while((argc > 1) && (strcmp(argv[i], "d") != 0)) {
    if(strcmp(argv[i], "a")) callMethodA(atoi(argv[i+1]));
    else if(strcmp(argv[i], "b")) callMethodB(atoi(argv[i+1]));
    else if(strcmp(argv[i], "c")) callMethodC(atoi(argv[i+1]));

    argc++;
    i+=2;
}

no limit is placed on the order of the commands or on the number of values cal

Answer 1

argv is a vector of char pointers. So each argv[i] is actually a memory address. Doing a regular comparison as argv[1] == "a" will not work since you are comparing memory locations.

What you want to do is use strcmp(argv[1], "a") . http://www.cplusplus.com/reference/cstring/strcmp/