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使用流,我如何 map HashMap 中的值?

[英]Using streams, how can I map the values in a HashMap?

Given a Map<String, Person> where Person has a String getName() (etc) method on it, how can I turn the Map<String, Person> into a Map<String, String> where the String is obtained from calling Person::getName() ?给定一个Map<String, Person> ,其中 Person 有一个String getName() (等)方法,我怎样才能将Map<String, Person>变成一个Map<String, String> ,其中String是从调用Person::getName()获得的Person::getName()

Pre-Java 8 I'd use我会使用 Pre-Java 8

Map<String, String> byNameMap = new HashMap<>();

for (Map.Entry<String, Person> person : people.entrySet()) {
    byNameMap.put(person.getKey(), person.getValue().getName());
}

but I'd like to do it using streams and lambdas.但我想使用流和 lambda 来做到这一点。

I can't see how to do this in a functional style: Map/HashMap don't implement Stream .我看不到如何以功能样式执行此操作: Map/HashMap 不实现Stream

people.entrySet() returns a Set<Entry<String, Person>> which I can stream over, but how can I add a new Entry<String, String> to the destination map? people.entrySet()返回一个Set<Entry<String, Person>>我可以在 ZF7B44CFFAFD5C52223D5498196C8A2E7BZ 上,但是如何将新的Entry<String, String>添加到目标 map?

With Java 8 you can do:使用 Java 8,您可以执行以下操作:

Map<String, String> byNameMap = new HashMap<>();
people.forEach((k, v) -> byNameMap.put(k, v.getName());

Though you'd be better off using Guava's Maps.transformValues , which wraps the original Map and does the conversion when you do the get , meaning you only pay the conversion cost when you actually consume the value.尽管您最好使用 Guava 的Maps.transformValues ,它包装原始Map并在您执行get时进行转换,这意味着您仅在实际消耗该值时才支付转换成本。

Using Guava would look like this:使用番石榴看起来像这样:

Map<String, String> byNameMap = Maps.transformValues(people, Person::getName);

EDIT:编辑:

Following @Eelco's comment (and for completeness), the conversion to a map is better done with Collectors.toMap like this:按照@Eelco 的评论(为了完整性),使用Collectors.toMap更好地转换为地图,如下所示:

Map<String, String> byNameMap = people.entrySet()
  .stream()
  .collect(Collectors.toMap(Map.Entry::getKey, (entry) -> entry.getValue().getName());

One way is to use a toMap collector:一种方法是使用toMap收集器:

import static java.util.stream.Collectors.toMap;

Map<String, String> byNameMap = people.entrySet().stream()
                                     .collect(toMap(Entry::getKey, 
                                                    e -> e.getValue().getName()));

Using a bit of generic code that I've sadly not found in the libraries I had at hand使用一些我手头的库中没有找到的通用代码

public static <K, V1, V2> Map<K, V2> remap(Map<K, V1> map,
        Function<? super V1, ? extends V2> function) {

    return map.entrySet()
            .stream() // or parallel
            .collect(Collectors.toMap(
                    Map.Entry::getKey, 
                    e -> function.apply(e.getValue())
                ));
}

This becomes essentially the same as Guavas Maps.transformValues minus the downsides mentioned by others.这与 Guavas Maps.transformValues基本相同,减去其他人提到的缺点。

Map<String, Person> persons = ...;
Map<String, String> byNameMap = remap(persons, Person::getName);

And in case you need the key as well as the value in your remapping function, this second version makes that possible如果您需要重新映射函数中的键和值,第二个版本使这成为可能

public static <K, V1, V2> Map<K, V2> remap(Map<K, V1> map,
        BiFunction<? super K, ? super V1, ? extends V2> function) {

    return map.entrySet()
            .stream() // or parallel
            .collect(Collectors.toMap(
                    Map.Entry::getKey,
                    e -> function.apply(e.getKey(), e.getValue())
                ));
}

It can be used for example like它可以用于例如

Map<String, String> byNameMap = remap(persons, (key, val) -> key + ":" + val.getName());

Since Java 9 you can also do:由于 Java 9 你也可以这样做:

Entry<String, String> entry = Map.entry("a", "b");

In your Map it would be used like this:在您的 Map 中,它将像这样使用:

Map<String, String> byNameMap = people.entrySet()
  .stream()
  .map(entry -> Map.entry(entry.getKey(), entry.getValue().getName()))
  .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue);

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