TypeError：正好接受4个参数（给定3个）：请求参数未被传递

Question

So i have this in my views.py

def rate_api(request, rating_user_id, rated_user_id, value):
    user.profile = request.user.get_profile()
    return HttpResponse('success')

And this in my urls.py

url(r'^rate_api/(?P<rating_user_id>.+?)/(?P<rated_user_id>.+?)/$', 'v1_1.views.rate_api'),

And this in my template (profile.html)

$.ajax({
          type: "GET",
          url: "../../rate_api/variable1/variable2/variable3",
          data: '',
        });

And I get the following error

TypeError at /rate_api/variable1/variable2/variable3/
rate_api() takes exactly 4 arguments (3 given)

Request Method: GET

I believe that the parameter request is not being passed. How can i fix this :/

Answer 1

不，它是未传递的value参数，因为您没有在正则表达式中捕获它。