[英]How to Deserialize a xml file's listed items which is present within another listed items
I have an auto generated xml file with the following format. 我有一个具有以下格式的自动生成的xml文件。
<?xml version="1.0"?>
<School>
<Classes numberOfFields="5">
<Class name="10" dataType="double">
<Section value="A"/>
<Section value="B"/>
<Section value="C"/>
</Class>
<Class dataType="double"/>
<Class dataType="double"/>
<Class dataType="double"/>
<Class dataType="double"/>
</Classes>
</School>
I deserialize using "XmlDeserializer" as follows 我使用“ XmlDeserializer”反序列化如下
School schoolResult = (School)xmlSerializer.Deserialize(stream);
XmlRootElement contains a collection of "Class" under "Classes" tag and further each "Class" would contain Collection of "Section". XmlRootElement在“类”标签下包含“类”的集合,并且每个“类”还将包含“部分”的集合。
And in C#, I have declared like this to deserialize "Classes" into a List of classes. 在C#中,我已经声明要像这样将“类”反序列化为类列表。
[XmlArray("Classes")]
[XmlArrayItem("Class", typeof(Class))]
public List<Class> Classes {};
Now to further deserialize Class into List of Sections, I have added the code as below. 现在,为了进一步将类反序列化为部分列表,我添加了以下代码。
[XmlArray("Class")]
[XmlArrayItem(ElementName="Section")]
public List<Section> ClassSections {};
My problem is I couldn't get the List of Sections values properly. 我的问题是我无法正确获取“节列表”值 。 Because I have "Class" as a class name in the first part and in second part I have mentioned same "Class" as Array element. 因为我在第一部分和第二部分中都将“ Class”作为类名,所以我提到了与“ Array”元素相同的“ Class”。 So could any one tell how can I properly Deserialize my "School" object using "XmlSerializer" to get all the values properly. 因此,谁能说出如何使用“ XmlSerializer”正确反序列化“ School”对象以正确获取所有值。
Note: I cannot have a Array root tag like "Sections" under "Class" . 注意:我不能 在“ Class”下有Array根标签,例如“ Sections” 。 Because my xml document is auto generated. 因为我的xml文档是自动生成的。 I cannot specify my own format. 我无法指定自己的格式。
Thanks... 谢谢...
try this : 尝试这个 :
public class School
{
[XmlAttribute]
public int numberOfFields { get; set; }
[XmlArray("Classes")]
[XmlArrayItem("Class", typeof(Class))]
public List<Class> Classes { get; set; }
}
public class Class
{
[XmlAttribute]
public string name { get; set; }
[XmlAttribute]
public string dataType { get; set; }
[XmlElement("Section")]
public List<Section> ClassSections { get; set; }
}
public class Section
{
[XmlAttribute]
public string value { get; set; }
}
* EDIT #1 ** *编辑#1 **
--------------- Update Structure due to NumberOfFields is not readed ---------------- ---------------由于NumberOfFields而导致的更新结构未读取----------------
in my opinion it's not correct structure, but when u said it's an auto generated XML file, i think it simplest way to read it. 我认为这不是正确的结构,但是当您说这是一个自动生成的XML文件时,我认为这是最简单的读取方法。
public class School
{
[XmlElement("Classes")]
public List<ArrayClass> Classes { get; set; }
}
public class ArrayClass
{
[XmlAttribute]
public int numberOfFields { get; set; }
[XmlElement("Class")]
public List<Class> Class { get; set; }
}
static void Main(string[] args)
{
var xml ="<?xml version=\"1.0\"?><School><Classes numberOfFields=\"5\"><Class name=\"10\" dataType=\"double\"><Section value=\"A\"/><Section value=\"B\"/><Section value=\"C\"/></Class><Class dataType=\"double\"/><Class dataType=\"double\"/><Class dataType=\"double\"/><Class dataType=\"double\"/></Classes></School>";
School result;
var serializer = new XmlSerializer(typeof(School));
var xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xml);
using (var reader = new XmlNodeReader(xmlDoc))
{
result = (School)serializer.Deserialize(reader);
}
}
public class School
{
[XmlArray("Classes")]
[XmlArrayItem("Class")]
public List<Class> Classes { get; set; }
}
public class Class
{
[XmlElement("Section")]
public List<Section> ClassSections { get; set; }
}
public class Section
{
[XmlAttribute("value")]
public string Value { get; set; }
}
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